WebDec 9, 2024 · Find the first letter in the string and check if it is upper case. If it is then add 1 to your count. Find the first non-letter after that point. Then find the first letter and compare again. Repeat until the end of the string. 1 solution Solution 1 Can you use regular expression ? Here is an example Let stick with loop each char Java Expand WebJun 22, 2024 · check one character at a time based on ASCII values. if (str [i] >= 65 and str [i] <=90), then it is uppercase letter, if (str [i] >= 97 and str [i] <=122), then it is lowercase …
C# Counting the Uppercase / Lowercase Words in a Text
WebApr 28, 2024 · In this loop, we check if character is a letter or digit by char.IsLetter () and char.IsDigit () method and increment in our counter variable. And for a special character, … WebJan 15, 2016 · Dictionary characterCount = input.ToLower () .Where (c => Char.IsLetter (c)) .GroupBy (c => c) .ToDictionary (k => k.Key, v => v.Count ()); To break each call down: ToLower () will convert the entire string into lower case - so we will count 'A' and 'a' as the same thing. honda cbr1100xx super blackbird radiator
Count Uppercase, Lowercase, special character and numeric values in C…
WebSep 2, 2015 · These two if s need not be nested: if (c == source [i + 1]) { charCount++; if (charCount >= sequenceLength) {. Instead of using a for loop, you could use a foreach … WebDec 9, 2024 · Find the first letter in the string and check if it is upper case. If it is then add 1 to your count. Find the first non-letter after that point. Then find the first letter and … WebFeb 9, 2015 · How to get indices of the capital letters in a string: def getindices (s): return [i for i, c in enumerate (s) if c.isupper ()] >>> getindices ('Hello') [0] >>> getindices ('HeLlO') [0, 2, 4] That fits my purpose for this problem I have, but doesn't answer the question I have (Get the indices of capital letters in a string), so I'll +1 this ... honda cbr 1100 super blackbird tuning